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content(docs): clean up unused parameter in code examples
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committed by
Jean-Philippe Sirois
parent
e4df60d22b
commit
1749ec3648
@@ -8,7 +8,7 @@ title: Simplifying Promises
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The first naive attempt, using new Promise for something that already returns a promise.
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```js
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function doAsync(number) {
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function doAsync() {
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return new Promise(function (resolve, reject) {
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doDatabase().then(function (dbResult) {
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otherDbFunction(dbResult).then(function (secondResult) {
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@@ -23,7 +23,7 @@ Turns out you don't need new Promise if you're working with a function that
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already returns a promise, you can just return the original thing.
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```js
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function doAsync(number) {
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function doAsync() {
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return doDatabase().then(function (dbResult) {
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otherDbFunction(dbResult).then(function (secondResult) {
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return secondResult + 10;
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@@ -36,7 +36,7 @@ You also don't have to nest `.then` functions, the whole point of promises
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is that they allow you to chain them sequentially.
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```js
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function doAsync(number) {
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function doAsync() {
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return doDatabase()
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.then(function (dbResult) {
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return otherDbFunction(dbResult);
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@@ -51,7 +51,7 @@ you also don't have to create a new function just to pass in one
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variable, you can pass in the entire function itself to the then block
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```js
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function doAsync(number) {
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function doAsync() {
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return doDatabase()
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.then(otherDbFunction)
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.then(function (secondResult) {
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@@ -63,7 +63,7 @@ function doAsync(number) {
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And you don't need those returns if you just have ES6 arrow functions
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```js
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const doAsync = (number) =>
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const doAsync = () =>
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doDatabase()
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.then(otherDbFunction)
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.then((secondResult) => secondResult + 10);
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