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Update how-to-create-a-linesegment-in-a-pathgeometry.md (#221)

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* Update how-to-create-a-linesegment-in-a-pathgeometry.md

Removed unnecessary [xaml] tags

* Update how-to-create-a-linesegment-in-a-pathgeometry.md

Co-authored-by: Andy De George <[email protected]>
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Christy
2021-03-08 17:19:59 -08:00
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co-authored by Andy De George
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dotnet-desktop-guide/framework/wpf/graphics-multimedia/how-to-create-a-linesegment-in-a-pathgeometry.md
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@@ -21,8 +21,6 @@ The following examples draw a <xref:System.Windows.Media.LineSegment> from (10,
![A LineSegment in a PathFigure](./media/graphicsmm-pathgeometrylinesegment.png "graphicsmm_pathgeometrylinesegment")
A LineSegment drawn from (10,50) to (200,70)
[xaml]
In [!INCLUDE[TLA#tla_xaml](../../../includes/tlasharptla-xaml-md.md)], you may use attribute syntax to describe a path.
```xaml
@@ -30,8 +28,6 @@ In [!INCLUDE[TLA#tla_xaml](../../../includes/tlasharptla-xaml-md.md)], you may u
Data="M 10,50 L 200,70" />
```
[xaml]
(Note that this attribute syntax actually creates a <xref:System.Windows.Media.StreamGeometry>, a lighter-weight version of a <xref:System.Windows.Media.PathGeometry>. For more information, see the [Path Markup Syntax](path-markup-syntax.md) page.)
In [!INCLUDE[TLA2#tla_xaml](../../../includes/tla2sharptla-xaml-md.md)], you may also draw a line segment by using object element syntax. The following is equivalent to the previous [!INCLUDE[TLA2#tla_xaml](../../../includes/tla2sharptla-xaml-md.md)] example.